Comments on: MySQL: Solution for ERROR 1442 (HY000): Can’t update table ‘t1′ in stored function/trigger because it is already used by statement which invoked this stored function/trigger.

By: cometinv3

cometinv3 — Tue, 15 Dec 2009 03:57:11 +0000

hola una pregunta nesecito ayuda nesecito hacer un trigger que cuando yo borre de una tabla un registro lo compare con una segunda tabla si el registro que fue borrado se en cuentra en la segunda tabla con el disparador se elimine cual seria mi solucion gracias espero sus respuestas en mysql podrian poner las posibles soluciones;

yo cree este trigger pero no se si esta bien

——————————
delimiter //
create trigger borrar
after delete on animales
for each row begin
delete animales,concursos from concursos,animales
where animales.cve_animal = concursos.cve_animal;
end
// delimiter
————————————

saludos

By: toro

toro — Mon, 19 Oct 2009 04:03:20 +0000

I use it and work find

DELIMITER |

CREATE TRIGGER shop_insert
BEFORE INSERT
ON shops
FOR EACH ROW
BEGIN
IF NEW.shop_id = NEW.shop_id THEN
SET NEW.created = NOW();
END IF;
END

DELIMITER ;

By: Jatin

Jatin — Wed, 24 Jun 2009 11:23:20 +0000

I got a msg when creating a view.

Error Code : 1142
CREATE VIEW command denied to user ‘root’@'user.com’ for table ‘tbl_ABC’

thanks in Advance..

By: Jhon Pierre

Jhon Pierre — Wed, 10 Jun 2009 14:38:25 +0000

I have a same problem. I create a trigger AFTER INSERT on tabla1 , in it i want to UPADTE the same tabla1 . But when i insert a row, i get the next error:

Error Code : 1442
Can’t update table ‘cuentacontable’ in stored function/trigger because it is already used by statement which invoked this stored function/trigger.
(32 ms taken)

Please. Help me, Thanks.

By: yayan suryaman

yayan suryaman — Mon, 01 Jun 2009 15:31:30 +0000

php myadmin error

By: Alvaro Oliver

Alvaro Oliver — Wed, 29 Apr 2009 19:40:35 +0000

Michael, TMD: same problem here!
what about updating different row in the same triggered table?

By: TMD

TMD — Mon, 16 Mar 2009 09:45:31 +0000

i need a solution to update DIFFERENT row in same table too, who can help??

By: Michael Hasenstein

Michael Hasenstein — Sun, 18 Jan 2009 02:23:03 +0000

Unfortunately this is NOT a solution to the problem. It only works if the record you want to update is the same record triggering the trigger.

What if I want to update a DIFFERENT row in the same table? For example, I’ve a tree stored in the table and want to update the parent_id’s in all affected rows when a row (node in the tree) is deleted. Impossible! What’s more, there is no reason for this mysql behavior. I use INNODB, which should have row-level locks. I’d understand the error in MYISAM tables which use table-locking.

Fact remains, it’s a really stupid mySQL bug. Oh well, one more reason to use a REAL database like Oracle

By: Herman

Herman — Mon, 17 Nov 2008 10:07:56 +0000

Hello!
I need a catalog tree table. How can I create trigger to check a column with “level of subcatalog”?
When some catalog moved into another all downlaying catalog must recount theirs level.
This is possible?

By: Tahir Mahmood

Tahir Mahmood — Thu, 02 Oct 2008 07:34:27 +0000

Hi friend,
I am facing problem in creating database. Would you please help me.

By: Sunny Walia

Sunny Walia — Sun, 15 Jun 2008 23:29:49 +0000

Cane, please use forums for questions not related to posts. I posted a correct table definition at: http://crazytoon.com/forum/viewtopic.php?f=3&t=6

By: cane

cane — Sun, 15 Jun 2008 03:19:26 +0000

Help with table, thanx up front!

DROP TABLE IF EXISTS `donations`;
CREATE TABLE `donations` (
`id` int(11) NOT NULL auto_increment,
`itemname` varchar(255) NOT NULL default ”,
`gross_price` varchar(10) NOT NULL default ”,
`pay_email` varchar(255) NOT NULL default ”,
`paymentdate` date NOT NULL default ‘0000-00-00′,
`firstname` varchar(100) default NULL,
`lastname` varchar(100) default NULL,
`memo` varchar(255) NOT NULL default ”,
`paymentstatus` varchar(20) default NULL,
`pendingreason` varchar(20) NOT NULL default ”,
`txnid` varchar(30) NOT NULL default ”,
`anom` char(3) NOT NULL default ‘no’,
`stdate` date default NULL,
KEY `paymentstatus` (`paymentstatus`),
KEY `stdate` (`stdate`),
KEY `txnid` (`txnid`)
) TYPE=MyISAM AUTO_INCREMENT=1;

#1075 – Incorrect table definition; there can be only one auto column and it must be defined as a key.

By: Phil

Phil — Tue, 10 Jun 2008 08:39:17 +0000

Thanks Tracy. This drop/create trigger gambit appears to be standard methodology. BUT, I am trying out Navicat and this seems to stand in the way of normal MySQL execution/saving/defining of MySQL objects.

By: Steve

Steve — Thu, 06 Mar 2008 07:39:48 +0000

Thanks for the great post. It helped me solve my problem with setting up my first trigger.

By: Jonathan Haddad

Jonathan Haddad — Tue, 04 Mar 2008 02:53:27 +0000

I actually had to read through this twice, because I was working on something similar at the time. If you’re trying to do an update-join, and one of the tables has a trigger that updates the other table in the join, it will fail.

For example, if you have these tables:
picture (pictureid, name, num_comments)
comment (commentid, pictureid, userid, comment, num_ratings),
rating (commentid, userid, rating)

Pictures have comments, comments have ratings.

If you’re trying to copy a foreign key from the comments to the ratings (say the pictureid, for performance reasons), and you have a trigger on ratings to update an aggregate in comments (in this case, the rating count), this query will fail:

update comment c JOIN rating r on c.commentid = r.commentid
set r.pictureid = c.pictureid;

You could get around it by only having the trigger fire if the rating changes.